If statement with String comparison fails

If an if statement with a string comparison fails in Java, it usually means that the strings being compared are not equal. This can be due to a number of reasons, such as:

• The strings have different characters.
• The strings have different case.
• The strings have different white space.
• One of the strings is null.

Here are some examples of string comparisons that may fail:

String s1 = "abc";
String s2 = "def";
if (s1.equals(s2)) {  // fails because s1 and s2 have different characters
    // ...
}

String s1 = "abc";
String s2 = "ABC";
if (s1.equals(s2)) {  // fails because s1 and s2 have different case
    // ...
}

String s1 = "abc";
String s2 = "  abc";
if (s1.equals(s2)) {  // fails because s1 and s2 have different white space
    // ...
}

String s1 = "abc";
String s2 = null;
if (s1.equals(s2)) {  // fails because s2 is null
    // ...
}

To fix the comparison failure, you can use the equalsIgnoreCase() method to compare the strings without considering case, or you can use the trim() method to remove leading and trailing white space from the strings before comparing them.

You can also use the == operator to compare the strings, but this only works if the strings are interned (i.e., they are the same object in memory).

I hope this helps! Let me know if you have any questions.