How do I get a class instance of generic type T?

To get a class instance of a generic type T, you can use the new operator and specify the type argument when creating an instance of the class. Here's an example:

class MyClass<T>
{
    T field;

    public MyClass(T t)
    {
        field = t;
    }
}

// Creating an instance of MyClass<int>
MyClass<int> instance = new MyClass<int>(5);

// Creating an instance of MyClass<string>
MyClass<string> instance2 = new MyClass<string>("hello");

Alternatively, you can use the Activator.CreateInstance method to create an instance of the class, like this:

MyClass<int> instance = (MyClass<int>)Activator.CreateInstance(typeof(MyClass<int>), 5);

MyClass<string> instance2 = (MyClass<string>)Activator.CreateInstance(typeof(MyClass<string>), "hello");

Keep in mind that if the class has multiple type parameters, you will need to specify values for all of them when creating an instance of the class.